Convert Foot-Pounds per Pound to Calories per Gram
Instantly convert Foot-Pounds per Pound (ft·lbf/lb) to Calories per Gram (cal/g) with our free online calculator.
Formula: ft·lbf/lb to cal/g — multiply by 7.1440e-4
Reference Table
| Foot-Pounds per Pound (ft·lbf/lb) | Calories per Gram (cal/g) |
|---|---|
| 1 | 0.000714405 |
| 5 | 0.00357202 |
| 10 | 0.00714405 |
| 25 | 0.0178601 |
| 50 | 0.0357202 |
| 100 | 0.0714405 |
How to Convert Foot-Pounds per Pound to Calories per Gram
Formula
To convert Foot-Pounds per Pound (ft·lbf/lb) to Calories per Gram (cal/g): multiply by 7.1440e-4
Step-by-Step
- Start with your value in Foot-Pounds per Pound (ft·lbf/lb).
- Multiply by 7.1440e-4 to perform the conversion.
- The result is your value expressed in Calories per Gram (cal/g).
Conversion Factor
1 ft·lbf/lb = 0.000714405 cal/g
Reverse Factor
1 cal/g = 1399.77 ft·lbf/lb
Worked Example
Convert 25 Foot-Pounds per Pound to Calories per Gram: 25 ft·lbf/lb = 0.0178601 cal/g
About Foot-Pound per Pound (ft·lbf/lb)
An imperial specific-energy unit equal to approximately 2.98907 J/kg (1 ft·lbf = 1.35582 J; 1 lb = 0.45359237 kg; ratio = 2.98907). ft·lbf/lb is a niche US-engineering unit used primarily in: ballistic kinetic-energy-per-mass calculations (E_k/m for projectiles, where US ballistics literature historically uses imperial mass for the projectile and ft·lbf for muzzle energy — a .308 Winchester 168gr bullet at 2,650 fps muzzle velocity has specific energy ~109,000 ft·lbf/lb), US-edition mechanical-engineering textbooks for mechanical strain-energy-per-mass calculations (Shigley, Norton, Hibbeler in dual-unit editions), and head-loss / hydraulic-energy specific calculations in US civil-engineering hydraulics where the natural unit is feet-of-head (1 ft of head of water ≈ 1 ft·lbf/lb specific gravitational potential). For typical engineering specific-energy scales (gasoline, batteries, structural-strain energy), the ft·lbf/lb numerical value is large and unwieldy — gasoline LHV is ~15.5 million ft·lbf/lb — so US engineers usually convert to BTU/lb for fuel work and reserve ft·lbf/lb for kinetic and elastic-strain applications. Convert ft·lbf/lb to J/kg by multiplying by 2.98907.
About Calorie per Gram (cal/g)
A CGS specific-energy unit equal to exactly 4,184 J/kg (using the thermochemical calorie definition per NIST SP 811), numerically identical to kcal/kg. cal/g is the working unit for chemistry reaction enthalpies per unit mass (heats of combustion measured in bomb calorimeters per ASTM D240 / D5865), food science nutritional energy (1 dietary 'Calorie' = 1 kcal = 1,000 cal — a confusing convention that persists despite ISO 80000-5 deprecation), thermochemistry per the NIST WebBook and Linstrom-Mallard NIST Standard Reference Database 69, and DSC (Differential Scanning Calorimetry) integration output for biological and pharmaceutical samples (TA Instruments, Mettler Toledo, PerkinElmer instruments default to cal/g for some legacy methods). Reference values per Atkins Physical Chemistry: water heat of vaporization at 100°C ≈ 540 cal/g; ice heat of fusion ≈ 80 cal/g; sucrose heat of combustion ≈ 3,940 cal/g; protein heat of combustion ≈ 4,100 cal/g; fats/oils ≈ 9,200 cal/g (the basis of the '9 calories per gram' nutritional rule of thumb for fat). Food labels outside the US showing 'kcal per 100g' display this unit scaled to a 100-gram serving size.
Quick Facts
- 1 Foot-Pound per Pound equals 0.000714405 Calories per Gram
- 1 Calorie per Gram equals 1399.77 Foot-Pounds per Pound
- Foot-Pound per Pound is a unit of specific energy
- Calorie per Gram is a unit of specific energy
- This conversion is commonly used in fuel comparison, battery technology, and rocket propulsion
- The Foot-Pound per Pound belongs to the imperial system
- The Calorie per Gram belongs to the metric system
Common Foot-Pound per Pound to Calorie per Gram Conversions
| Foot-Pounds per Pound (ft·lbf/lb) | Calories per Gram (cal/g) |
|---|---|
| 0.01 | 0.00000714405 |
| 0.1 | 0.0000714405 |
| 0.25 | 0.000178601 |
| 0.5 | 0.000357202 |
| 1 | 0.000714405 |
| 2 | 0.00142881 |
| 3 | 0.00214321 |
| 5 | 0.00357202 |
| 10 | 0.00714405 |
| 15 | 0.0107161 |
| 20 | 0.0142881 |
| 25 | 0.0178601 |
| 50 | 0.0357202 |
| 75 | 0.0535804 |
| 100 | 0.0714405 |
| 250 | 0.178601 |
| 500 | 0.357202 |
| 1000 | 0.714405 |
| 5000 | 3.57202 |
| 10000 | 7.14405 |
Understanding Foot-Pounds per Pound
The Foot-Pound per Pound (symbol: ft·lbf/lb) is a unit of specific energy. An imperial specific-energy unit equal to approximately 2.98907 J/kg (1 ft·lbf = 1.35582 J; 1 lb = 0.45359237 kg; ratio = 2.98907). ft·lbf/lb is a niche US-engineering unit used primarily in: ballistic kinetic-energy-per-mass calculations (E_k/m for projectiles, where US ballistics literature historically uses imperial mass for the projectile and ft·lbf for muzzle energy — a .308 Winchester 168gr bullet at 2,650 fps muzzle velocity has specific energy ~109,000 ft·lbf/lb), US-edition mechanical-engineering textbooks for mechanical strain-energy-per-mass calculations (Shigley, Norton, Hibbeler in dual-unit editions), and head-loss / hydraulic-energy specific calculations in US civil-engineering hydraulics where the natural unit is feet-of-head (1 ft of head of water ≈ 1 ft·lbf/lb specific gravitational potential). For typical engineering specific-energy scales (gasoline, batteries, structural-strain energy), the ft·lbf/lb numerical value is large and unwieldy — gasoline LHV is ~15.5 million ft·lbf/lb — so US engineers usually convert to BTU/lb for fuel work and reserve ft·lbf/lb for kinetic and elastic-strain applications. Convert ft·lbf/lb to J/kg by multiplying by 2.98907.
It belongs to the imperial measurement system.
Foot-Pounds per Pound are commonly used in fuel comparison, battery technology, and rocket propulsion.
Understanding Calories per Gram
The Calorie per Gram (symbol: cal/g) is a unit of specific energy. A CGS specific-energy unit equal to exactly 4,184 J/kg (using the thermochemical calorie definition per NIST SP 811), numerically identical to kcal/kg. cal/g is the working unit for chemistry reaction enthalpies per unit mass (heats of combustion measured in bomb calorimeters per ASTM D240 / D5865), food science nutritional energy (1 dietary 'Calorie' = 1 kcal = 1,000 cal — a confusing convention that persists despite ISO 80000-5 deprecation), thermochemistry per the NIST WebBook and Linstrom-Mallard NIST Standard Reference Database 69, and DSC (Differential Scanning Calorimetry) integration output for biological and pharmaceutical samples (TA Instruments, Mettler Toledo, PerkinElmer instruments default to cal/g for some legacy methods). Reference values per Atkins Physical Chemistry: water heat of vaporization at 100°C ≈ 540 cal/g; ice heat of fusion ≈ 80 cal/g; sucrose heat of combustion ≈ 3,940 cal/g; protein heat of combustion ≈ 4,100 cal/g; fats/oils ≈ 9,200 cal/g (the basis of the '9 calories per gram' nutritional rule of thumb for fat). Food labels outside the US showing 'kcal per 100g' display this unit scaled to a 100-gram serving size.
It belongs to the metric measurement system.
Calories per Gram are commonly used in fuel comparison, battery technology, and rocket propulsion.
Why Convert Foot-Pounds per Pound to Calories per Gram?
Converting between Foot-Pounds per Pound and Calories per Gram is a frequent requirement for engineers, scientists, and students working with specific energy values. Different industries and regions favour different unit systems, so having a dependable conversion tool saves time and prevents errors in technical calculations. Whether you are verifying a specification sheet, cross-checking simulation results, or preparing a report for an international audience, accurate specific energy conversion is essential.
Frequently Asked Questions
How do I convert Foot-Pounds per Pound to Calories per Gram?
An imperial specific-energy unit equal to approximately 2. To convert Foot-Pounds per Pound to Calories per Gram, multiply by 7.1440e-4. For example, 25 ft·lbf/lb equals 0.0178601 cal/g.
How many Calories per Gram are in 1 Foot-Pound per Pound?
There are 0.000714405 Calories per Gram in 1 Foot-Pound per Pound.
How many Foot-Pounds per Pound are in 1 Calorie per Gram?
There are 1399.77 Foot-Pounds per Pound in 1 Calorie per Gram.
What is the formula for Foot-Pound per Pound to Calorie per Gram conversion?
The formula is: multiply by 7.1440e-4. This means 1 ft·lbf/lb = 0.000714405 cal/g.
Is a Foot-Pound per Pound bigger than a Calorie per Gram?
Yes. One Foot-Pound per Pound is larger than one Calorie per Gram because 1 ft·lbf/lb equals 0.000714405 cal/g, which is less than 1.
When do you need to convert between Foot-Pounds per Pound and Calories per Gram?
A CGS specific-energy unit equal to exactly 4,184 J/kg (using the thermochemical calorie definition per NIST SP 811), numerically identical to kcal/kg. Foot-Pound per Pound and Calorie per Gram are both specific energy units, so conversion comes up whenever one source of information uses one unit and another uses the other — a classic cross-reference challenge in engineering, trade, travel, and everyday life.