Annulus Area Calculator
Calculate the area of an annulus (ring shape) using A = PI*(R^2 - r^2), where R is the outer radius and r is the inner radius. Essential for engineering washers, pipe cross-sections, circular tracks, orbital mechanics, and ring-shaped design elements.
This free online annulus area calculator provides instant results with no signup required. All calculations run directly in your browser — your data is never sent to a server. Enter your values below and see results update in real time as you type. Perfect for everyday calculations, homework, or professional use.
Minimum: 0.01
Radius of the outer circle
Minimum: 0
Radius of the inner circle (must be less than outer radius)
Results
Annulus Area
201.0619 sq units
How to Use This Calculator
Enter your input values
Fill in all required input fields for the Annulus Area Calculator. Most fields include unit selectors so you can work in your preferred unit system — metric or imperial, whichever matches your problem.
Review your inputs
Double-check that all values are correct and that you have selected the right units for each field. Incorrect units are the most common source of calculation errors and can produce results that are off by factors of 2, 10, or more.
Read the results
The Annulus Area Calculator instantly computes the output and displays results with units clearly labeled. All calculations happen in your browser — no loading time and no data sent to a server.
Explore parameter sensitivity
Try adjusting individual input values to see how the output changes. This is a quick and effective way to develop intuition about how different parameters influence the result and to identify which inputs have the largest effect.
When to Use This Calculator
- •Use the Annulus Area Calculator when you need a quick mathematical result without writing out all the steps manually, saving time on repetitive calculations.
- •Use it to verify hand calculations on tests or assignments and catch arithmetic mistakes.
- •Use it when teaching or explaining mathematical concepts to others, demonstrating how changing inputs affects the result.
- •Use it to explore the behavior of mathematical functions across a range of inputs.
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About Annulus Area Calculator
The Annulus Area Calculator computes the area of the ring-shaped region between two concentric circles using A = PI*(R^2 - r^2). An annulus is formed when a smaller circle is removed from the center of a larger circle. This shape appears constantly in everyday life and engineering: washers, gaskets, pipe cross-sections, circular running tracks, CDs and DVDs, tree ring cross-sections, and orbital paths of satellites. The formula subtracts the inner circle area from the outer circle area. The factored form PI*(R+r)*(R-r) is useful for computations and reveals that the annulus area depends on both the sum and difference of the radii.
The Math Behind It
Formula Reference
Annulus Area
A = pi * (R^2 - r^2)
Variables: R = outer radius, r = inner radius
Alternative (factored)
A = pi * (R + r) * (R - r)
Variables: Uses difference of squares factorization
Worked Examples
Example 1: Circular Running Track
A running track has inner radius 30 m and outer radius 35 m. Find the track area.
The track area is approximately 1021.02 square meters.
Example 2: Washer
A flat washer has outer radius 10 mm and inner radius 6 mm.
The washer area is approximately 201.06 square mm.
Common Mistakes & Tips
- !Subtracting radii instead of squaring them first: pi*(R-r)^2 is NOT the annulus area. You must square each radius separately and then subtract.
- !Swapping the inner and outer radii, which would give a negative result. R must be greater than r.
- !Using diameter instead of radius. If given diameters, divide each by 2 before applying the formula.
Related Concepts
Used in These Calculators
Calculators that build on or apply the concepts from this page:
Frequently Asked Questions
Can I find the annulus area from a single tangent chord?
Yes. If a chord of the outer circle is tangent to the inner circle and has length L, then the annulus area is pi*L^2/4. This works because by the Pythagorean theorem, (L/2)^2 = R^2 - r^2, so pi*(R^2 - r^2) = pi*L^2/4.
Why are hollow shafts stronger per unit weight than solid ones?
The material far from the center contributes more to torsional and bending resistance than material near the center. A hollow shaft (annular cross-section) removes the less effective central material while keeping the more effective outer material, giving a better strength-to-weight ratio.
What if the inner radius is zero?
When r = 0, the annulus becomes a full circle with area pi*R^2. The formula handles this edge case correctly.
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