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Torsion Calculator

Calculate shear stress and angle of twist for solid and hollow circular shafts under torsion

Reviewed by Christopher FloiedUpdated

This free online torsion calculator provides instant results with no signup required. All calculations run directly in your browser — your data is never sent to a server. Supports both metric (SI) and imperial units with built-in unit selection dropdowns on every input field, so you can work in whatever units your problem provides. Designed for engineering students and professionals working through coursework, design projects, or quick reference calculations.

Torsion Calculator

Calculate shear stress and angle of twist for circular shafts under torque.

Steel ≈ 80 GPa · Aluminum ≈ 26 GPa

Results

Max Shear Stress τ_max

20.3718 MPa

= 2.0372e+7 Pa

Angle of Twist θ

0.5836°

= 0.010186 rad

Polar Moment J

6.1359e-7 m⁴

Formulas

J = πd⁴/32 = π×5.000e-2⁴/32
J = 6.1359e-7 m⁴
τ_max = Tr/J = 500 × 0.0250 / 6.1359e-7
τ_max = 20.3718 MPa
θ = TL/(GJ) = 500 × 1 / (80 GPa × 6.1359e-7)
θ = 0.010186 rad = 0.5836°

How to Use This Calculator

1

Enter your input values

Fill in all required input fields for the Torsion Calculator. Most fields include unit selectors so you can work in your preferred unit system — metric or imperial, whichever matches your problem.

2

Review your inputs

Double-check that all values are correct and that you have selected the right units for each field. Incorrect units are the most common source of calculation errors and can produce results that are off by factors of 2, 10, or more.

3

Read the results

The Torsion Calculator instantly computes the output and displays results with units clearly labeled. All calculations happen in your browser — no loading time and no data sent to a server.

4

Explore parameter sensitivity

Try adjusting individual input values to see how the output changes. This is a quick and effective way to develop intuition about how different parameters influence the result and to identify which inputs have the largest effect.

Formula Reference

Shear Stress in Shaft

τ = T·r / J

Variables: T = applied torque, r = radial distance from center, J = polar moment of inertia

Angle of Twist

φ = T·L / (G·J)

Variables: L = shaft length, G = shear modulus

When to Use This Calculator

  • Use the Torsion Calculator when solving homework or exam problems that require quick numerical verification of your hand calculations — instant feedback helps identify arithmetic errors before they propagate.
  • Use it during the early design phase to rapidly iterate on parameters and narrow down feasible configurations before committing time to detailed finite element simulations or full design packages.
  • Use it when reviewing a colleague's calculation or checking a vendor's data sheet for plausibility — a quick sanity check can prevent costly downstream errors.
  • Use it to generate reference data for a technical report or presentation without manual computation, ensuring consistent, reproducible numbers throughout the document.
  • Use it in the field when a quick estimate is needed and a full engineering software package is not available.

About This Calculator

The Torsion Calculator is a precision engineering calculation tool designed for students, engineers, and technical professionals. Calculate shear stress and angle of twist for solid and hollow circular shafts under torsion All calculations are performed using established engineering formulas from the relevant scientific literature and standards. Inputs support both metric (SI) and imperial unit systems, with unit conversion handled automatically — simply select your preferred unit from the dropdown next to each field. Results are computed instantly in the browser without sending data to a server, ensuring both speed and privacy. This calculator is intended as a supplementary tool for learning and design exploration; always verify results against authoritative references for safety-critical applications.

The Theory Behind It

Torsion refers to twisting of a shaft about its longitudinal axis under applied torque. For circular cross-sections (solid or hollow), the shear stress varies linearly from zero at the axis to a maximum at the outer surface: τ = T·r/J, where T is the applied torque, r is the radial distance from the axis, and J is the polar moment of inertia. For a solid circle of radius R, J = πR⁴/2; for a hollow circle, J = π(R_out⁴ − R_in⁴)/2. The maximum shear stress occurs at the outer surface: τ_max = TR/J. The angle of twist (relative rotation of one end of the shaft relative to the other) is φ = TL/(GJ), where L is the shaft length and G is the shear modulus. These formulas are exact for circular cross-sections because the cross-section remains plane and circular during twisting — an important symmetry property. For non-circular cross-sections (rectangles, I-sections, open thin-walled sections), the analysis is much more complex: cross-sections warp out of plane during twisting, and the stress distribution involves both shear stress and a stress concentration at corners. Non-circular torsion is treated using specialized formulas and the St. Venant theory. In practice, power transmission shafts are nearly always circular because circular sections are both the most efficient carriers of torque and the easiest to manufacture on a lathe. Hollow shafts give 90-95% of the torsional strength of solid shafts of the same outer diameter but with only 50-60% of the material, making them significantly more efficient and lighter. The design approach for shafts is to compute the maximum shear stress under the expected torque, compare with allowable shear stress (typically yield in shear, which is about 0.577 × tensile yield for ductile metals), and verify the angle of twist is within deflection limits (often 1° per meter for precision machinery).

Real-World Applications

  • Drive shaft design: power transmission shafts in cars, trucks, and industrial machinery carry torque from an engine or motor to a driven component. Size the shaft diameter so maximum shear stress stays below allowable.
  • Helical spring analysis: wound helical springs experience torsion in the wire cross-section, with maximum stress at the inner surface. The torsion formula combined with the Wahl correction factor gives the peak stress in spring design.
  • Fastener torquing analysis: when a bolt is torqued, the shank experiences torsion that combines with axial tension to produce a combined stress state. Torsion analysis is needed for high-strength bolts and for dynamic applications.
  • Automotive steering shaft: steering shafts connect the steering wheel to the steering gear through multiple intermediate couplings and shafts. Torsion analysis sizes the shaft diameter and checks stiffness for steering feel.
  • Wind turbine shaft: the main shaft of a wind turbine carries the torque generated by the rotor blades to the gearbox and generator. Large wind turbines have shaft torques in the range of 1-10 MN·m, requiring careful torsional design.

Frequently Asked Questions

What is the formula for shear stress in a circular shaft?

τ = T·r/J, where T is the applied torque, r is the distance from the center, and J is the polar moment of inertia (J = πD⁴/32 for a solid circle of diameter D, or J = π(D₀⁴ − Dᵢ⁴)/32 for a hollow shaft). The maximum stress is at the outer surface: τ_max = TR/J = 16T/(πD³) for a solid shaft. The stress is zero at the center and varies linearly with radius.

What is the angle of twist?

The angle of twist is the relative rotation of one end of a shaft with respect to the other under applied torque: φ = TL/(GJ), where T is torque, L is the shaft length, G is the shear modulus, and J is the polar moment of inertia. For a steel shaft (G = 77 GPa), 1 m long, 50 mm diameter, under 1000 N·m: φ = 1000·1/(77×10⁹ · π·0.05⁴/32) ≈ 0.0423 rad ≈ 2.42°.

Why are circular shafts used for torque transmission?

Circular cross-sections are the most efficient shape for carrying torque because: (1) they have the highest J for a given area and weight, maximizing torsional stiffness; (2) the stress distribution is well-understood (linear in radius); (3) manufacturing is easy on a lathe; (4) cross-sections remain plane during twisting, eliminating warping stresses that occur in non-circular shapes; (5) they have no stress concentrations from corners. For power transmission, there is no practical alternative to circular shafts.

Is a hollow shaft better than a solid shaft?

Yes, in most cases. A hollow shaft uses material more efficiently because the maximum stress is at the outer surface and the center material does very little work. A hollow shaft with outer diameter D and inner diameter 0.6D has about 90% of the torsional capacity of a solid shaft of diameter D but only about 65% of the weight. Hollow shafts are especially valuable in aerospace and automotive applications where weight matters. The main disadvantage is added manufacturing complexity.

How do I calculate the torque in a shaft from horsepower?

T = P/ω, where P is power (W = N·m/s) and ω is angular velocity (rad/s). In practical units: T (N·m) = 9549 × P(kW) / N(RPM). A 100 kW motor at 1800 RPM delivers 9549 × 100 / 1800 = 530 N·m of torque. In imperial: T (lb·ft) = 5252 × P(hp) / N(RPM), so a 100 hp engine at 1800 RPM produces 292 lb·ft.

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References & Further Reading